Question

Calculate the partial pressure of propane in a mixture that contains equal numbers of of moles of propane (C3H8) and butane (C4H10) at 20 degrees C and 844 mmHg. (R=0.082 L-atm/K mol)

Answer 1

equal number of mols propane and butane means Xbutane = 0.5 and Xpropane = 0.5
Then pbutane = Xbutane*Ptotal
ppropane = Xpropane*Ptotal