Asked by Tasha

What is the partial pressure of O2 in the lungs if the atmospheric pressure (total pressure) is 755mmHG, the PN2 is 561mmHg, PCO2 is 0.29mmHg, and PH2O in the lungs is 41mmHg?
Answered by DrBob222
Ptotal = sum of partial pressures.
755 = pN2 + pH2O + pCO2 + pO2
Substitute the numbers and solve for pO2 in mm Hg.
Post your work if you get stuck.
Answered by Tasha
So, am I adding all of them and then divided by 755?
Answered by DrBob222
No.
755 = 561 + 41 + 0.29 + pO2
Solve for pO2 of substitute X for pO2 and solve for X
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