Asked by ******tasha******
If the critical angle of a liquid is 41.4 degrees find the index of refraction for that liquid
Answers
Answered by
Elena
sin α(cr) = 1 / n,
n= 1/sin α(cr) = 1/sin 41.4 =1.51
n= 1/sin α(cr) = 1/sin 41.4 =1.51
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