Asked by Evans
what is the critical angle for light passing from(n=1.54) to (n=1.33)
Answers
Answered by
bobpursley
Snell's law: N<sub>i</sub>*sin(Theta<sub>i</sub>)= N<sub>t</sub>*sin(Theta<sub>t</sub>)
but at critical angle Theta<sub>t</sub>=90 so
SinTheta<sub>c</sub>= N<sub>t</sub>/N<sub>i</sub>=1.33/1.54=0.864 or
Theta<sub>critical</sub>=59.7 deg
but at critical angle Theta<sub>t</sub>=90 so
SinTheta<sub>c</sub>= N<sub>t</sub>/N<sub>i</sub>=1.33/1.54=0.864 or
Theta<sub>critical</sub>=59.7 deg
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