Asked by Priscilla
Find the derivative
** (sq root)
y = (square root) x + (2nd sq root) x +
(3rd sq root) x
** All the x's is under three sq roots
y' = 1/2(sq rt) x + 1/(sq rt) x +
3/2(sq rt) x
Is this right?
** (sq root)
y = (square root) x + (2nd sq root) x +
(3rd sq root) x
** All the x's is under three sq roots
y' = 1/2(sq rt) x + 1/(sq rt) x +
3/2(sq rt) x
Is this right?
Answers
Answered by
Bosnian
Go on: wolframalpha dot com
When page be open in rectangle type:
derivative your expresion
and click option =
After few seconds when you see result click option:
Show steps
If square root) x + (2nd sq root) x +
(3rd sq root) x
mean
sqrt(x )+2*sqrt(x)+3*sqrt(x)
type:
derivative sqrt(x )+ 2* sqrt(x)+3*sqrt(x)
and click option =
then
Show steps
On wolfram alpha dot com you can practice any kind ofCalculus
When page be open in rectangle type:
derivative your expresion
and click option =
After few seconds when you see result click option:
Show steps
If square root) x + (2nd sq root) x +
(3rd sq root) x
mean
sqrt(x )+2*sqrt(x)+3*sqrt(x)
type:
derivative sqrt(x )+ 2* sqrt(x)+3*sqrt(x)
and click option =
then
Show steps
On wolfram alpha dot com you can practice any kind ofCalculus
Answered by
Priscilla
ok thank you
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.