Asked by Priscilla

Find the derivative

** (sq root)

y = (square root) x + (2nd sq root) x +
(3rd sq root) x

** All the x's is under three sq roots

y' = 1/2(sq rt) x + 1/(sq rt) x +
3/2(sq rt) x


Is this right?

Answers

Answered by Bosnian
Go on: wolframalpha dot com

When page be open in rectangle type:


derivative your expresion

and click option =


After few seconds when you see result click option:

Show steps

If square root) x + (2nd sq root) x +
(3rd sq root) x

mean

sqrt(x )+2*sqrt(x)+3*sqrt(x)


type:

derivative sqrt(x )+ 2* sqrt(x)+3*sqrt(x)

and click option =

then

Show steps


On wolfram alpha dot com you can practice any kind ofCalculus


Answered by Priscilla
ok thank you
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