Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
In a hydraulic lift, the radii of the pistons are 2.93 cm and 10.1 cm. A car weighing W = 11.0 kN is to be lifted by the force...Asked by Akbar
In a hydraulic lift, the radii of the pistons are 2.93 cm and 10.1 cm. A car weighing W = 11.0 kN is to be lifted by the force of the large piston.
(a) What force Fa must be applied to the small piston? 925.7 N
(b) When the small piston is pushed in by 10.4 cm, how far is the car lifted? mm
b. h2 = h1•(A1/A2) = h1•(r/R) = 3.02 cm
(c) Find the mechanical advantage of the lift, which is the ratio W / Fa.
11.9
Sorry for reposting, but i don't know why part b is wrong the answer has to be in mm, so 3.02 cm would be 30.2 mm, but it giving me wrong; please help. Thank you.
(a) What force Fa must be applied to the small piston? 925.7 N
(b) When the small piston is pushed in by 10.4 cm, how far is the car lifted? mm
b. h2 = h1•(A1/A2) = h1•(r/R) = 3.02 cm
(c) Find the mechanical advantage of the lift, which is the ratio W / Fa.
11.9
Sorry for reposting, but i don't know why part b is wrong the answer has to be in mm, so 3.02 cm would be 30.2 mm, but it giving me wrong; please help. Thank you.
Answers
Answered by
bobpursley
part b is wrong because you did (A1/A2)=(r/R)
the ratio of radii should be squared...
the ratio of radii should be squared...
Answered by
Akbar
Thank you!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.