Question
Elle is pushing a box of mass 7.0 kilograms with the force of 25 newtons. If the force of friction is 2.6 newtons, what is the value of acceleration of the box?
Answers
Elena
F-F(fr) = m•a
a =(F-F(fr))/m =(25 – 2.6)/7 =3.2 m/s^2
a =(F-F(fr))/m =(25 – 2.6)/7 =3.2 m/s^2
Anonymous
xfbdf