Asked by mafika
calculate the 16th term of an arithmatic progression he its fifth term is 6 and its 12th is 41.
Answers
Answered by
Steve
a+4d = 6
a+11d = 41
7d = 35
d = 5
a = -14
-14 + 15(5) = 61
a+11d = 41
7d = 35
d = 5
a = -14
-14 + 15(5) = 61
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