Asked by Hamna
                The 16th term of an AP is three times the 5th term. If the 12th term is 20 more than the 7th term, find the first term and the common difference.
            
            
        Answers
                    Answered by
            Scott
            
    5 d = 20 ... d = 4
T5 + 11d = 3 T5 ... T5 = 22
T1 = T5 - 4d
    
T5 + 11d = 3 T5 ... T5 = 22
T1 = T5 - 4d
                    Answered by
            christine
            
    a= 5, d=7
    
                    Answered by
            twitter:@legitlongwe 
            
    Tn=a +(n-1)d
T12 = 20+T7,
a +11d = 20 + a + 6d,
5 d = 20, d = 4.
T16 = 3T5,
a + (16 - 1)d = 3[a+(5-1)d],
a + (16 - 1)4 = 3[a+(5-1)4],
a+60 =3a+48,
3a-a = 60 - 48.
2a = 12
a= 6
a = 6, d = 4
    
T12 = 20+T7,
a +11d = 20 + a + 6d,
5 d = 20, d = 4.
T16 = 3T5,
a + (16 - 1)d = 3[a+(5-1)d],
a + (16 - 1)4 = 3[a+(5-1)4],
a+60 =3a+48,
3a-a = 60 - 48.
2a = 12
a= 6
a = 6, d = 4
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