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Answers (1)
Tn=a +(n-1)d T12 = 20+T7, a +11d = 20 + a + 6d, 5 d = 20, d = 4. T16 = 3T5, a + (16 - 1)d = 3[a+(5-1)d], a + (16 - 1)4 = 3[a+(5-1)4], a+60 =3a+48, 3a-a = 60 - 48. 2a = 12 a= 6 a = 6, d = 4
