Asked by JB

ã3tanx=3tanxcscx-ã3tanx
Answered by JB
those are supposed to be square root symbols. I'm not sure what happened...
Answered by Reiny
so you want

√(3tanx) = 3tanxcscx - √(3tanx)
then
2√(3tanx) = 3 (sinx/cosx)(1/sinx))
= 3/cosx
square both sides
4(3tanx) = 9/cos^2 x
12 sinx/cosx = 9/cos^2 x
12 sinx = 9/cosx
12 sinxcosx = 9
2 sinxcosx = 9/6 = 3/2
sin (2x) = 3/2

But the sine of anything cannot > 1

your equation has no real solution.
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