The derivative of f(x) is
-1-3/x²
Don't know how you got -1, or what the question really is.
Use the shortcut rules to mentally calculate the derivative of the given function
f(x) = −x + (3/x) + 1
After deriving it, I got
-1+(0/1)+0= -1
But this answer is wrong, and I don't know why.
Thank You
3 answers
How did you get the answer? I don't quite understand. Thanks
If f(x)=g(x)+h(x), then
linearity gives
f'(x)=g'(x)+h'(x)
so
f(x)=-x + (3/x) + 1
f'(x)= (-x)' + (3/x)' + (1)'
=-1 -3/x² + 0
=-1 -3/x²
The second term is obtained by the power rule:
d(1/x)/dx = -1/x²
linearity gives
f'(x)=g'(x)+h'(x)
so
f(x)=-x + (3/x) + 1
f'(x)= (-x)' + (3/x)' + (1)'
=-1 -3/x² + 0
=-1 -3/x²
The second term is obtained by the power rule:
d(1/x)/dx = -1/x²