Question
The ionization constant of HA is 4.0e-4. Using the ice table what is the equilibrium concentration of HA in terms of its initial concentration and x?
HA(aq) + H2O(l) = H3O^+^(aq) + A^-^(aq)
I 0.040M OM OM
C -X +x +x
E ? x x
I thought that to find the concentration you need to do 0.040-x=4.0e-4 but I am not sure if this is correct.
HA(aq) + H2O(l) = H3O^+^(aq) + A^-^(aq)
I 0.040M OM OM
C -X +x +x
E ? x x
I thought that to find the concentration you need to do 0.040-x=4.0e-4 but I am not sure if this is correct.
Answers
DrBob222
It is 0.04-x.
Hannah
oh ok I see, thank you.