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What is the ionization constant for a weak acid HA that is 1.60% ionized in 0.095M solution?
7 years ago

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DrBob222
........HA ==> H^+ + A^-
I......0.095...0.....0

So (H^+) = (A^-) = 0.095*0.016

Substitute into Ka expression and solve for Ka.
7 years ago

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