Question
Which is the oxidizing agent in the reaction below.
Cr2O72- + 6S2O32- +14H+ > 2Cr3+ + 3S4O62- +7H20
A. Cr3+
B. S4O62-
C. Cr2O62-
D. S2O32-
E. H+
I believe it's D or is it C not 100% sure please help. THANKS
Cr2O72- + 6S2O32- +14H+ > 2Cr3+ + 3S4O62- +7H20
A. Cr3+
B. S4O62-
C. Cr2O62-
D. S2O32-
E. H+
I believe it's D or is it C not 100% sure please help. THANKS
Answers
DrBob222
The oxidizing agent is the substance that is reduced. I assume you made an typo in C and it should be Cr2O7^2-.
VUENTO
ANSWER IS Cr2O7^2-