Asked by Debbie

Which is the oxidizing agent in the reaction below.

Cr2O72- + 6S2O32- +14H+ > 2Cr3+ + 3S4O62- +7H20

A. Cr3+
B. S4O62-
C. Cr2O62-
D. S2O32-
E. H+

I believe it's D or is it C not 100% sure please help. THANKS
Answered by DrBob222
The oxidizing agent is the substance that is reduced. I assume you made an typo in C and it should be Cr2O7^2-.
Answered by VUENTO
ANSWER IS Cr2O7^2-
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