Asked by Debbie

_________is reduced in the following reaction:

Cr2O72-+6S2O32-+14H+>2Cr3+ + 3S4O62- + 7H20

A. H+ B. Cr6+ C. S4O62- D. S2+ E. O2-

I come out with Cr2O72 but that's not an answer so my next one is B. Cr6+ am I correct?
Answered by DrBob222
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