Question

A saturated solution of a certain metal(II) chloride has a chloride ion concentration of 0.032M. The Ksp for this compound can be determined to be

a) 2.6 X 10-7

b) 4.1 X 10-6

c) 1.6 X 10-5

d) 2.6 X 10-4

e) 1.6 X 10-2

I am unsure how to approach this problem or the steps to take to achieve the solution. Thank you

Answer 1

Let x = solubility of MCl2
MCl2 ==> M^2+ + 2Cl^-
..x.......x......2x
Ksp = (Mg^2+)(Cl^-)^2
If (Cl^-) = 0.032 then (M^2+) must be 1/2 that. Substitute into Ksp expression and solve.

Answer 2

i still don't get this

Answer 3

(.032^2)x(.016^-1)^2
=4