Question

In a saturated solution of Zn(OH)2 at 25 degrees Celsius the value of [OH-] is 2.0x10^-6M. What is the value of the solubility-product constant, Ksp, for Zn(OH)2 at 25 degrees Celsius?

A. 4x10^-18
B. 8x10^-18
C. 1.6x10^-17
D. 4x10^-12
E. 2x10^-6

Help?
Thank you!

Answer 1

Zn(OH)2 ==> Zn^+2 + 2OH^-

Ksp = (Zn^+2)(OH^-)^2
(OH^-) = 2 x 10^-6 M.
(Zn^+2) must be 1 x 10^-6 M
Substitute into Ksp and solve.

Answer 2

Ksp = (1x10^-6)(2x10^-6)^2
Ksp = 4.0 x 10^-18

Answer 3

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Answer 4

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