Al(OH)3 ==> Al^+3 + 3OH^-
If the concn of OH^- is 2.6 x 10^-5 mol/L, then the Al^+3 concn must be 1/3 of that. Note: I think you meant the concn OH^- was 2.6 x 10^-5 and NOT 2.6 x 10^5.
In a saturated solution of Al(OH)3 the concentration of OH^1- is 2.6 x 10^5 mol/L. The concentration of Al3+ in mol/L is what?
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