Asked by kathy
The width of a rectangle is 3 cm less than the length. The area of the rectangle is 54 square cm. Find the width and length of the rectangle.
Answers
Answered by
Steve
I'll work with the width, since the letter l and the digit 1 look similar.
if the length is 3 more than the width,
w(w+3) = 54
w^2 + 3w = 54
w^2 + 3w - 54 = 0
(w+9)(w-6) = 0
w=6 (can't have negative width)
the rectangle is 6x9
if the length is 3 more than the width,
w(w+3) = 54
w^2 + 3w = 54
w^2 + 3w - 54 = 0
(w+9)(w-6) = 0
w=6 (can't have negative width)
the rectangle is 6x9
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