the width of a rectangle is 1 ft less than the length, the area is 6 ft^2, what is the length and width? thank you

Answer 1

L * (L-1) = 6
L^2 -L -6 = 0
(L-3)(L+2) = 0
take it from there

Answer 2

L*W=area
L(L-1)=6
solve for L
L^2-L-6=0
(L-3)(L+2)=9
L=3, W=2

Answer 3

thanks bob, for all your help