Asked by Diana
the width of a rectangle is 1 ft less than the length, the area is 6 ft^2, what is the length and width? thank you
Answers
Answered by
Damon
L * (L-1) = 6
L^2 -L -6 = 0
(L-3)(L+2) = 0
take it from there
L^2 -L -6 = 0
(L-3)(L+2) = 0
take it from there
Answered by
bobpursley
L*W=area
L(L-1)=6
solve for L
L^2-L-6=0
(L-3)(L+2)=9
L=3, W=2
L(L-1)=6
solve for L
L^2-L-6=0
(L-3)(L+2)=9
L=3, W=2
Answered by
diana
thanks bob, for all your help
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