THE WIDTH OF A RECTANGLE IS TWO-FIFTH OF THE LENGTH . WHAT ARE THE DIMENSION IF THE PERIMETER IS 112 FEET?

Answer 1

W = Width

L = Lentgh

P = Perimeter

W = ( 2 / 5 ) L

P = 2 W + 2 H

112 = 2 ( 2 / 5 ) L + 2 L

( Remark : 2 L = ( 10 / 5 ) L )

112 = ( 4 / 5 ) L + ( 10 / 5 ) L

112 = ( 14 / 5 ) L Multiply both sides with 5

112 * 5 = 14 L

560 = 14 L Diwide both sides with 14

560 / 14 = L

L = 40 ft

W = ( 2 / 5 ) L

W = ( 2 * 40 ) / 5

W = 80 / 5

W = 16 ft

P = 2W + 2 H

P = 2 * 16 + 2 * 40

P = 32 + 80

P = 112 ft