Asked by lovemore
A student swings a 3.5g rubber stopper in a horizontal circle over her head.The length of the string is 0.6m.The stopper is observed to make 10 revolutions in 11.7seconds.What is the tangential velocity of the stopper at any time,t.
Answers
Answered by
drwls
The tangential speed at any time is
V = 10*(2*pi*R)/11.7 s = 3.375 m/s
The mass of the stopper has nothing to to with it.
The direction of the tangential veloity is forward and perpendical to the string. It keeps changing.
V = 10*(2*pi*R)/11.7 s = 3.375 m/s
The mass of the stopper has nothing to to with it.
The direction of the tangential veloity is forward and perpendical to the string. It keeps changing.
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