Asked by dafina
A man swings his child in a circle of radius 0.75 m .If the mass of child is 25 kg and the child makes one revolution in 1.5 s,what are the magnitude and direction of the force that must be exerted by the man on the child?*assume that the child to be a point particle
Answers
Answered by
drwls
Vertical force component = M*g
Radial force component = M V^2/R
V = 2*pi*R/(1.5 s)= 3.142 m/s
R = 0.75 m
M = 25 kg
Do the numbers and compute the magnitude.
Radial force component = M V^2/R
V = 2*pi*R/(1.5 s)= 3.142 m/s
R = 0.75 m
M = 25 kg
Do the numbers and compute the magnitude.