Question
A spherical snowball is melting so that its diameter is decreasing at rate of 0.1 cm/min. At what is the rate is the volume of the snowball changing when the diameter is 12 cm?
Answers
if diameter decreases at .01 cm/min
then dr/dt = -.005 cm/min
Vol = (4/3)π r^3
d(Vol)/dt = 4π r^2 dr/dt
d(Vol)/dt = 4π(36)(-.005) = .....
then dr/dt = -.005 cm/min
Vol = (4/3)π r^3
d(Vol)/dt = 4π r^2 dr/dt
d(Vol)/dt = 4π(36)(-.005) = .....