Question
a spherical snowball with diameter 4 inches is removed from the freezer in June and begins melthing uniformly such that it is shrinking 2 cubic inches per minute. How fast ( in square inches per minute) is the surface area decreasing when the radius is 1 inch?
Answers
..it is shrinking 2 cubic inches per minute ----> dV/dt = -2 cubic inches/min
V = (4/3)pi(r^3)
dV/dt = 4pi(r^2)dr/dt
when r - 1 and dV/dt = -2
-2 = 4pi(1)dr/dt
dr/dt = -1/(2pi)
but A = 4pi(r^2)
then dA/dt = 8pi(r)dr/dt
so again when r=1
dA/dt = 8pi(1)(-1/2pi)
=-4 square inches/min
V = (4/3)pi(r^3)
dV/dt = 4pi(r^2)dr/dt
when r - 1 and dV/dt = -2
-2 = 4pi(1)dr/dt
dr/dt = -1/(2pi)
but A = 4pi(r^2)
then dA/dt = 8pi(r)dr/dt
so again when r=1
dA/dt = 8pi(1)(-1/2pi)
=-4 square inches/min
Related Questions
A spherical snowball is melting so that its diameter is decreasing at rate of 0.1 cm/min. At what is...
The radius of a spherical snowball is decreasing at a rate of 2 inches per hour. How fast is the sno...
Jake stores a small cache of4-inch-diameter snowballs in the basement freezer, unaware that the free...