Asked by Anonymous
10. An aqueous solution is prepared by diluting 3.30 mL acetone, CH3COCH3, (d=0.789 g/mL) with water to a final volumeof 75.0 mL. The density of the solution is 0.993 g/mL. What is the molarity and molality of acetone in this solution?
Answers
Answered by
bobpursley
Molarity= massAcetone/formulamass *1/.0033
massAcetone= density*volume
calculate molarity.
Finally, molarity= massAcetone/formulamass*1/(.075-.0033)
massAcetone= density*volume
calculate molarity.
Finally, molarity= massAcetone/formulamass*1/(.075-.0033)
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