Asked by Becca
Preform the operation and write in standard form:
(8+20i)/(2i)
(8+20i)/(2i)
Answers
Answered by
Steve
multiply top and bottom by i:
i(8+20i)/2i^2
= (8i + 20i^2)/-2
= (-20 + 8i)/-2
= 10 - 4i
i(8+20i)/2i^2
= (8i + 20i^2)/-2
= (-20 + 8i)/-2
= 10 - 4i
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