Perform the operation and write the result in standard form.
(√19 + √20i)(√19 – √20i)
4 answers
19 - 20i
@OOF I tried that. It's saying that it's wrong
i reworked it a bunch of times and i'm stumped. i'm sorry
since (a+b)(a-b) = a^2-b^2
(√19 + √20i)(√19 – √20i)
= 19 - 20i^2 = 19+20 = 39
(a-bi)(a+bi) = a^2+b^2
(√19 + √20i)(√19 – √20i)
= 19 - 20i^2 = 19+20 = 39
(a-bi)(a+bi) = a^2+b^2
1 answer