Asked by Nathan
A 0.5kg puck traveling in a horizontal circle of radius 3.2m has a frequency of 0.5Hz. what is the centripetal force on the cord?
Answers
Answered by
drwls
The angular frequency is
W = 2*pi*0.5 = pi = 3.14 rad/s
The centripetal force is
F = M*R*W^2 = 1.6 pi^2 = 15.8 N
W = 2*pi*0.5 = pi = 3.14 rad/s
The centripetal force is
F = M*R*W^2 = 1.6 pi^2 = 15.8 N
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