Asked by Nathan

A 0.5kg puck traveling in a horizontal circle of radius 3.2m has a frequency of 0.5Hz. what is the centripetal force on the cord?
Answered by drwls
The angular frequency is
W = 2*pi*0.5 = pi = 3.14 rad/s

The centripetal force is

F = M*R*W^2 = 1.6 pi^2 = 15.8 N