Asked by anonymous
In a physics lab, 0.30 kg puck A, moving at 5.0 m/s [W], undergoes a collision with 0.40 kg puck B, which is initially at rest. Puck A moves off at 4.2 m/s [W 30° N]. Find the final velocity of puck B.
Answers
Answered by
oobleck
conserve momentum.
0.30<-5,0> = 0.30<-3.63,2.1> + 0.40<vx,vy>
solve for vx,vy the components of puck B's velocity
0.30<-5,0> = 0.30<-3.63,2.1> + 0.40<vx,vy>
solve for vx,vy the components of puck B's velocity
Answered by
henry2,
Given: M1 = 0.30 kg, V1 = -5.0 m/s.
M2 = 0.40 kg, V2 = 0.
V3 = 4.2 m/s[150o] CCW = velocity of M1 after collision.
V4 = velocity of M2 after collision.
M1*V1+M2*V2 = M1*V3+M2*V4.
0.30*(-5)+0.40*0 = 0.30*4.2[150o]+0.40*V4
-1.50 = 1.26[150o]+0.40*V4
-1.5 = -1.09+0.63i + 0.4*V4
-0.4*V4 = 0.41+0.63i
V4 = -1.025-1.575i = 1.88m/s[57o] S. of W. = velocity of puck B.
M2 = 0.40 kg, V2 = 0.
V3 = 4.2 m/s[150o] CCW = velocity of M1 after collision.
V4 = velocity of M2 after collision.
M1*V1+M2*V2 = M1*V3+M2*V4.
0.30*(-5)+0.40*0 = 0.30*4.2[150o]+0.40*V4
-1.50 = 1.26[150o]+0.40*V4
-1.5 = -1.09+0.63i + 0.4*V4
-0.4*V4 = 0.41+0.63i
V4 = -1.025-1.575i = 1.88m/s[57o] S. of W. = velocity of puck B.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.