Asked by Labz

How do you solve 7^(3x) = 8^(2x)

Answers

Answered by Steve
ln(7^3x) = ln(8^2x)
3xln7 = 2xln8
x(3ln7 - 2ln8) = 0

Looks like x=0
7^0 = 8^0
a lot of work for nothing.
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