Asked by Tiffany
Work of 700 J is done by stirring an insulated beaker containing 110 g of water.
(a) What is the change in the internal energy of the system?
J
(b) What is the change in the temperature of the water?
°C
(a) What is the change in the internal energy of the system?
J
(b) What is the change in the temperature of the water?
°C
Answers
Answered by
drwls
(a) 700 J
(b) (Internal Energy Increase)/[(Specific Heat)*Mass]
= (700J/4.184 J/cal)/(110g*1.00 cal/g*C)
= 1.5 C
(b) (Internal Energy Increase)/[(Specific Heat)*Mass]
= (700J/4.184 J/cal)/(110g*1.00 cal/g*C)
= 1.5 C
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