Asked by MJ
An aqueous solution is 0.257 m NaOH. What are the boiling point and freezing point of this solution?
Answers
Answered by
DrBob222
delta Tf = i*Kf*m for freezing point.
delta Tb = i*Kb*m for boiling point.
For f.p., subtract delta T from normal freezing point.
For b.p., add delta T to normal boiling point.
delta Tb = i*Kb*m for boiling point.
For f.p., subtract delta T from normal freezing point.
For b.p., add delta T to normal boiling point.
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