Question

Calculate the vapor pressure lowering of water when 5.67 g of glucose, C6H12O6, is dissolved in 25.2 g of water at 25 ºC. The vapor pressure of water at 25º C is 23.8 mmHg. What is the vapor pressure of the solution?
mols glucose = g/molar mass
mols H2O = grams/molar mass

XH2O = n H2O/total mols, then
Psoln = XH2O*P<sup>o</sup><sub>normal</sub>

For lowering, use
delta P<sub>solvent</sub> =X<sub>solute</sub>*P<sup>o</sup><sub>normal</sub>
100 gram solution of 10 gram of magnesium.klorida and 90 gram of water what is the vapor pressure lowering of a solution if p h2o=31 mmhg

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