Asked by PleaseHelp
calculate the vapor pressure of a solution made by dissolving 61.7g (molar mass= 60.06g/mol) of Urea in 212ml of water at 35C. what is the vapor pressure lowering? the vapor pressure of water at 35c =31.82 mmHg
Answers
Answered by
DrBob222
mols urea = grams/molar mass
mols H2O = grams/molar mass
Xurea = nurea/total mols from above.
XH2O = nH2O/total mols.
PH2O = Xurea*P<sup>o</sup><sub>H2O</sub>
Lowering is
Plowering = XH2O*P<sup>o</sup><sub>H2O</sub>
mols H2O = grams/molar mass
Xurea = nurea/total mols from above.
XH2O = nH2O/total mols.
PH2O = Xurea*P<sup>o</sup><sub>H2O</sub>
Lowering is
Plowering = XH2O*P<sup>o</sup><sub>H2O</sub>
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