Asked by karlo

there are 4 white balls and 6 red balls in a sack. If two balls are taken out successively ( the first ball is not replaced ) what is the probability that the balls are drawn are of different colors?
Answered by bobpursley
pr= prob second white given first red, plus prob second red given first white.

pr= 4/9*6/10 + 6/9*4/10= 48/90
Answered by sajith
A box contains 10 balls of which 6 are red (R) and 4 are white (W) . Three balls are taken from the box at random, one after the other. The probability that the 3 balls drawn are in the order RRW is equal to,
Answered by uu
xdf_ghdf
Answered by john
tommy has 7 yellows 6 green 3 blues 8 red wht it tommy probability that she will not draw a green ball
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