Question

A diver is jumping straight up with 2 m/s from a 15 meter platform. Calculate the maximum height of the diver, the diver’s velocity when reaches the water, and total time to reach the water.

Answer 1

max height: new PE=initial KE
mgh=1/2 mv^2
h= 1/2 v^2/g

velocity at impact
KE at impact= PE lost+ initial KE
1/2 m v^2= mg(15)+1/2 m 2^2
solve for v.

Total time.
hf=hi+vi*t - 4.8t^2
0=15+2t-4.8t^2

solve the quadratic, use the quadratic equation to solve for t.

Answer 2

Thanks bobpursely I need this for my Quantitative Biomechanics class