Question

The reaction described by this equation
O3(g) + NO(g) -- O2(g) + NO2(g)
has the following rate law at 310 K.
rate of reaction = 3.0x10^6 M^-1 s^-1)[O3][NO]
Given that [O3]=2.0× 10–4 M and [NO]=2.0× 10–5 M at t=0, calculate the rate of the reaction at t=0.

Answer 1

rate rxn = k[O3][NO]
Substitute for k and each of the cncns (given in the problem) and solve for rate of rxn.

Answer 2

Given that [O3]=4.0× 10–4 M and [NO]=3.0× 10–5 M at t=0, calculate the rate of the reaction at t=0.

Answer 3

90

Answer 4

.012