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Asked by Debbie

Checking to see if I did this right?

Titration of HN03 titrated with NaOH
ending result is 1.38.

Titration A, endpoint pH = 8 is pKa or pKb= 1.38x106=5.861 and

Titration of NH03 titrated with KOH ending results 1.54.

Titration B, endpoint pH = 7 is KaorKb=
Ka=1.54x105
13 years ago

Answers

Answered by DrBob222
Beats me. I don't know what you're describing.
13 years ago

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