Question

What volume of 3.0M sodium hydroxide will be needed to neutralize 2.0 L of 1.0M hydrochloric acid?

Answer 1

How many mols HCl? M x L = mols.
HCl + NaOH ==> NaCl + H2O
1:1; therefore, mols NaOH = moles HCl.
M NaOH = moles NaOH/L NaOH. Solve for L.

Answer 2

Naoh+Hcl==>Nacl+H2o
1:1for mole
Mole of Naoh = mole of Hcl
That is mean :
M of Naoh ×volume of Naoh = M of Hcl ×volume of Hcl
3×v=1×2 ====»3v =2
V=2\3 liter
The volume of Naoh=2/3 liter