Asked by william
To obtain 80 mol of sodium hydroxide (NaOH) from the electrolysis of an aqueous solution of NaCl, where
70% of its mass is water, what mass of this solution, in kg, should be used?
70% of its mass is water, what mass of this solution, in kg, should be used?
Answers
Answered by
Anonymous
how much does 80 mol of NaCl weigh ?
Na = 23 g/mol then * 80 = 1840 grams
Cl =35.5 g/mol then * 80 = 2840 grams
sum = 4680 grams of NaCl = 30% of the mass
so
mass = 4680 grams/ 0.30 * 1 kg/1000 grams = 15.6 kg
Na = 23 g/mol then * 80 = 1840 grams
Cl =35.5 g/mol then * 80 = 2840 grams
sum = 4680 grams of NaCl = 30% of the mass
so
mass = 4680 grams/ 0.30 * 1 kg/1000 grams = 15.6 kg
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.