Asked by Anonymous
You have 480 grams of a radioactive kind of tin. If its half-life is 10 days, how much will be left after 30 days?
Answers
Answered by
Bosnian
After 10 days you have half left
After 20 days that's half of the half again = a quarter
After 30 days that's half of a quarter = an eighth
480 / 8 = 60 grams
After 20 days that's half of the half again = a quarter
After 30 days that's half of a quarter = an eighth
480 / 8 = 60 grams
Answered by
Bosnian
Equation :
N( t ) = N( 0 ) * ( 1 / 2 ) ^ [ t / t( 1 / 2) ]
In this case :
N ( 30 ) = 480 * ( 1 / 2 ) ^ ( 30 / 10 )
N ( 30 ) = 480 * ( 1 / 2 ) ^ 3
N ( 30 ) = 480 * 1 / 8 = 60 grams
N( t ) = N( 0 ) * ( 1 / 2 ) ^ [ t / t( 1 / 2) ]
In this case :
N ( 30 ) = 480 * ( 1 / 2 ) ^ ( 30 / 10 )
N ( 30 ) = 480 * ( 1 / 2 ) ^ 3
N ( 30 ) = 480 * 1 / 8 = 60 grams
Answered by
Bosnian
Also you can in google type:
half-life equation
and click : en.wikipedia
half-life equation
and click : en.wikipedia
Answered by
Anonymous
Suppose that a certain radioactive substance has a half-life of 20 years. If there are presently 2400 milligrams of the substance, how much, to the nearest milligram, will remain after 70 years?
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