Asked by Shahab Mirza

If we take 2.2 grams of CO2, 6.02 X 1021 atomes of nitrogen and 0.03 gram atoms of sulphar , then the molar ratio of C, N, and O is .

answer is 5:1 :3

how to solve it help please , thanks
Answered by DrBob222
2g CO2 x (atomic mass C/molarmass CO2) = approx 0.6 mols C
6.02E21/6.02E23 = 0.01 mols N
0.03 mols O
but that isn't 5:1:3 but more like 60:1:3

Answered by Shahab Mirza
@DrBob222 , thanks for reply, thanks sir
Answered by DrBob222
Sorry but I made an error above in the conversions and the 5:1:3 IS right after all.
mols CO2 = g/molar mass = 2.2/44 = 0.05. I convert to grams C which isn't right. mols C is the same as mols CO2; therefore, we have
mols C = 0.05
mols N = 0.01
mols O = 0.03
and the ratio is C5NO3
Answered by Shahab Mirza
@DrBob222 , Thanks sir, but I still cant understand , help me out,
see , 2.2g X 12/44 = 0.6 moles of CO2, so how to calculate Moles of N and O ?
Answered by SHoaib
If 0.03 gram atoms of sulfur is given then why ratio of oxygen is asked.....so basicaly there is error in question ratio of Sulfur should be asked instead of Oxygen so
Moles of C=0.05
Moles of N=6.02x10^21/6.02x10^23=0.01
Moles of S=0.03 (1gram atoms = 1mole)
So Ratio is 5:1:3

Answered by Sammy
How can we find moles of oxygen? Plz answer: DrBob222 , Shahab Mirza
Answered by Soha
How did u calculate the moles of sulphur .. plz help!
Answered by Akansha
It's already given
Answered by Asad
How to calculate moles for O by this data? Please answer it.
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