7 of 107 of 10 Items Question Calculate and compare the surface area of sphere A, which has a radius of 2 in., and sphere B, which has a radius of 10 in. The formula for the surface area of a sphere is 4πr 2 .(1 point) Responses Sphere A has a surface area of 2π in. and sphere B has a surface area of 10π in., meaning sphere B’s surface area is 4 times as large as sphere A’s. Sphere A has a surface area of 2π in. and sphere B has a surface area of 10π in., meaning sphere B’s surface area is 4 times as large as sphere A’s. Sphere A has a surface area of 4π in. and sphere B has a surface area of 100π in., meaning sphere B’s surface area is 25 times as large as sphere A’s. Sphere A has a surface area of 4π in. and sphere B has a surface area of 100π in., meaning sphere B’s surface area is 25 times as large as sphere A’s. Sphere A has a surface area of 16π in. and sphere B has a surface area of 400π in., meaning sphere B’s surface area is 25 times as large as sphere A’s. Sphere A has a surface area of 16π in. and sphere B has a surface area of 400π in., meaning sphere B’s surface area is 25 times as large as sphere A’s. Skip to navigation page 1 of 1

1 answer

To calculate and compare the surface area of the two spheres, we will use the formula for the surface area of a sphere, which is:

\[ \text{Surface Area} = 4\pi r^2 \]

  1. Sphere A:

    • Radius \( r = 2 \) in.
    • Surface Area \( = 4\pi(2^2) = 4\pi(4) = 16\pi \) in².
  2. Sphere B:

    • Radius \( r = 10 \) in.
    • Surface Area \( = 4\pi(10^2) = 4\pi(100) = 400\pi \) in².

Now, let's compare the surface areas:

  • Sphere A has a surface area of \( 16\pi \) in².
  • Sphere B has a surface area of \( 400\pi \) in².

To find out how many times larger Sphere B’s surface area is compared to Sphere A’s surface area, we can divide the two surface area values:

\[ \frac{400\pi}{16\pi} = \frac{400}{16} = 25 \]

Thus, Sphere B's surface area is 25 times as large as Sphere A’s.

Therefore, the correct response is:

Sphere A has a surface area of \( 16\pi \) in.² and sphere B has a surface area of \( 400\pi \) in.², meaning sphere B’s surface area is 25 times as large as sphere A’s.