To calculate the surface area of spheres A and B using the formula for the surface area of a sphere \( S = 4\pi r^2 \):
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Sphere A (radius = 6 in): \[ S_A = 4\pi(6^2) = 4\pi(36) = 144\pi \text{ in}^2 \]
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Sphere B (radius = 24 in): \[ S_B = 4\pi(24^2) = 4\pi(576) = 2304\pi \text{ in}^2 \]
Now, to compare the surface areas:
- The surface area of sphere A is \( 144\pi \text{ in}^2 \).
- The surface area of sphere B is \( 2304\pi \text{ in}^2 \).
To find out how many times larger sphere B's surface area is than sphere A's, divide the surface area of sphere B by the surface area of sphere A: \[ \frac{S_B}{S_A} = \frac{2304\pi}{144\pi} = \frac{2304}{144} = 16 \]
Thus, sphere B's surface area is 16 times as large as sphere A's.
Final Answer:
Sphere A has a surface area of \( 144\pi \text{ in}^2 \), and sphere B has a surface area of \( 2304\pi \text{ in}^2 \). This means that sphere B’s surface area is 16 times as large as sphere A’s.
The correct response is: Sphere A has a surface area of 144π in.² and sphere B has a surface area of 2,304π in.². This means that sphere B’s surface area is 16 times as large as sphere A’s.