assuming your table is:
x: -10, -4, -1, 3
y: -3, 0, 2, 4, and not some kind of absolute value relation,
the slope between pairs of point is ...
(-3-0)/(-10+4) = -3/-6 = 1/2
.. (4-2)/(3+1) = 1/2
but (2-0)/(-1+4) = 2/3
so the relationship is not linear according to my assumption.
If you do imply absolute values, then just make all the data values
positive and test for slope
Furthermore, just type fractions like 2/3 instead of in words.
7. Is the relationship shown by the data linear? If it is, model the data with an equation. *
x | -10 | -4 |-1 | 3
y | -3 | 0 | 2 | 4
The relationship is linear. y – 4 = 1 over 2(x – 3)
The relationship is linear. y = 2 over 2(x + 4)
The relationship is linear. y – 10 = 1 over 2(x – 3)
The relationship is not linear.
2 answers
it's linear if it has a constant slope.
In this case, it's not.
In this case, it's not.
7 answers