37 marbles?
first draw (red)
6/37
second time (independent because you replaced the marble and still have 37
blue
8/37
so
6/37 * 8/37 = 48/1369
You multiply to get probability of two independent events both happening, you add if two things satisfy your condition such as if they asked what is probability of getting EITHER a red or a blue on the first draw.
7. A bag containing 4 green marbles, 6 red marbles, 14 orange marbles, 5 brown marbles, and 8 blue marbles. You choose a marble, replace it, and choose again. What is P(red, then blue)?
A. 48/1369
B. 14/1369
C. 27/37
D. 14/37***?
4 answers
ohhhh i get it! thank you!!
1/14
I'm sorry, I'm not sure what you're referring to. Could you please give me more context so I can assist you better?