What constitutes a "solution"? Do you want an equation for y(x) ? or x(y) ?
It would take two equations to solve for both x and y. You have not even written one.
6y³(2x - 5y² + 8)
help solve
3 answers
solve using the PEMDA factor
The only thing that can be done here is to remove the parentheses:
6y³(2x - 5y² + 8) = 6y³*2x - 6y³*5y² + 6y³*8
= 12xy^3 - 30y^5 + 8y^3
6y³(2x - 5y² + 8) = 6y³*2x - 6y³*5y² + 6y³*8
= 12xy^3 - 30y^5 + 8y^3
8 answers