Asked by Jeremy
Hi,
Please provide assistance on the following problem. I worked out part of it, but do not know what to do after calculating pH for HCl.
Suppose you dissolved 0.0365 grams of HCl in water to give a final volume of 10.0 mL. The molar mass of HCl is 36.5 g/mole and the molar mass of water is 18.0 g/mole. What is the pH of this final solution?
This is what I have so far: [HCl]=.001 mole of HCl/0.010 liters = 0.10M
[H3O+]= 0.10M= 1.00 x 10^-1.
Now, I am not sure what I need to do.
Thanks!
Please provide assistance on the following problem. I worked out part of it, but do not know what to do after calculating pH for HCl.
Suppose you dissolved 0.0365 grams of HCl in water to give a final volume of 10.0 mL. The molar mass of HCl is 36.5 g/mole and the molar mass of water is 18.0 g/mole. What is the pH of this final solution?
This is what I have so far: [HCl]=.001 mole of HCl/0.010 liters = 0.10M
[H3O+]= 0.10M= 1.00 x 10^-1.
Now, I am not sure what I need to do.
Thanks!
Answers
Answered by
DrBob222
pH = -log(H^+)
Substitute and solve for pH.
Substitute and solve for pH.
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